10 lines
503 B
SQL
10 lines
503 B
SQL
SELECT temp.site, temp.percentage AS "% of HNQ", temp.questions AS "# of HNQ", t.number_of_questions AS "# of all Q on site",
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ROUND(100.0 * questions / t.number_of_questions, 2) AS "% of all Q on site"
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FROM (SELECT site, ROUND(100.0 * COUNT(*) / (SELECT COUNT(*) FROM snapshots), 2) AS "percentage",
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COUNT(DISTINCT(question)) AS "questions"
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FROM snapshots
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GROUP BY site
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ORDER BY COUNT(*) DESC
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) AS temp
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INNER JOIN total_question_count AS t on t.site = temp.site
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ORDER BY 2 DESC |