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[Bugfix] Re arrange Regex for Duration, fixing issue if inaccurate results. (#239)
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1 changed files with 19 additions and 15 deletions
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@ -1139,21 +1139,8 @@ interface LoadResponse {
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fun getDurationFromString(input: String?): Int? {
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val cleanInput = input?.trim()?.replace(" ", "") ?: return null
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Regex("([0-9]*)h.*?([0-9]*)m").find(cleanInput)?.groupValues?.let { values ->
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if (values.size == 3) {
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val hours = values[1].toIntOrNull()
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val minutes = values[2].toIntOrNull()
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if (minutes != null && hours != null) {
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return hours * 60 + minutes
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}
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}
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}
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Regex("([0-9]*)m").find(cleanInput)?.groupValues?.let { values ->
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if (values.size == 2) {
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return values[1].toIntOrNull()
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}
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}
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Regex("(\\s\\d+\\shr)|(\\s\\d+\\shour)|(\\s\\d+\\smin)|(\\s\\d+\\ssec)").findAll(input).let { values ->
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//Use first as sometimes the text passes on the 2 other Regex, but failed to provide accurate return value
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Regex("(\\d+\\shr)|(\\d+\\shour)|(\\d+\\smin)|(\\d+\\ssec)").findAll(input).let { values ->
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var seconds = 0
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values.forEach {
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val time_text = it.value
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@ -1174,6 +1161,23 @@ fun getDurationFromString(input: String?): Int? {
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return seconds / 60
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}
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}
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Regex("([0-9]*)h.*?([0-9]*)m").find(cleanInput)?.groupValues?.let { values ->
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if (values.size == 3) {
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val hours = values[1].toIntOrNull()
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val minutes = values[2].toIntOrNull()
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if (minutes != null && hours != null) {
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return hours * 60 + minutes
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}
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}
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}
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Regex("([0-9]*)m").find(cleanInput)?.groupValues?.let { values ->
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if (values.size == 2) {
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val return_value = values[1].toIntOrNull()
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if (return_value != null) {
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return return_value
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}
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}
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}
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return null
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}
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