fix: ユーザー検索で、クエリがusernameの条件を満たす場合はusernameもLIKE検索するように (#8644)
* Fix #8643 * 部分一致にする
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					 1 changed files with 8 additions and 1 deletions
				
			
		|  | @ -61,7 +61,14 @@ export default define(meta, paramDef, async (ps, me) => { | |||
| 			.getMany(); | ||||
| 	} else { | ||||
| 		const nameQuery = Users.createQueryBuilder('user') | ||||
| 			.where('user.name ILIKE :query', { query: '%' + ps.query + '%' }) | ||||
| 			.where(new Brackets(qb => {  | ||||
| 				qb.where('user.name ILIKE :query', { query: '%' + ps.query + '%' }); | ||||
| 
 | ||||
| 				// Also search username if it qualifies as username
 | ||||
| 				if (Users.validateLocalUsername(ps.query)) { | ||||
| 					qb.orWhere('user.usernameLower LIKE :username', { username: '%' + ps.query.toLowerCase() + '%' }); | ||||
| 				} | ||||
| 			})) | ||||
| 			.andWhere(new Brackets(qb => { qb | ||||
| 				.where('user.updatedAt IS NULL') | ||||
| 				.orWhere('user.updatedAt > :activeThreshold', { activeThreshold: activeThreshold }); | ||||
|  |  | |||
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