JH hash compiler workarounds

- Fixed uninitialized `state->x` warning
- Fixed broken code with `-O3` or `-Ofast`

The old code is known to break GCC 10.1 and GCC 11.4
This commit is contained in:
SChernykh 2023-10-27 14:09:58 +02:00
parent d9b765a3af
commit e7d51e5583

View file

@ -34,7 +34,7 @@ typedef struct {
unsigned long long databitlen; /*the message size in bits*/
unsigned long long datasize_in_buffer; /*the size of the message remained in buffer; assumed to be multiple of 8bits except for the last partial block at the end of the message*/
DATA_ALIGN16(uint64 x[8][2]); /*the 1024-bit state, ( x[i][0] || x[i][1] ) is the ith row of the state in the pseudocode*/
unsigned char buffer[64]; /*the 512-bit message block to be hashed;*/
DATA_ALIGN16(unsigned char buffer[64]); /*the 512-bit message block to be hashed;*/
} hashState;
@ -213,16 +213,24 @@ static void E8(hashState *state)
/*The compression function F8 */
static void F8(hashState *state)
{
uint64 i;
uint64_t* x = (uint64_t*)state->x;
/*xor the 512-bit message with the fist half of the 1024-bit hash state*/
for (i = 0; i < 8; i++) state->x[i >> 1][i & 1] ^= ((uint64*)state->buffer)[i];
for (int i = 0; i < 8; ++i) {
uint64 b;
memcpy(&b, &state->buffer[i << 3], sizeof(b));
x[i] ^= b;
}
/*the bijective function E8 */
E8(state);
/*xor the 512-bit message with the second half of the 1024-bit hash state*/
for (i = 0; i < 8; i++) state->x[(8+i) >> 1][(8+i) & 1] ^= ((uint64*)state->buffer)[i];
for (int i = 0; i < 8; ++i) {
uint64 b;
memcpy(&b, &state->buffer[i << 3], sizeof(b));
x[i + 8] ^= b;
}
}
/*before hashing a message, initialize the hash state as H0 */
@ -240,6 +248,7 @@ static HashReturn Init(hashState *state, int hashbitlen)
case 224: memcpy(state->x,JH224_H0,128); break;
case 256: memcpy(state->x,JH256_H0,128); break;
case 384: memcpy(state->x,JH384_H0,128); break;
default:
case 512: memcpy(state->x,JH512_H0,128); break;
}