Fix bug in mempool get_transaction_stats histogram calculation

The 98th percentile position in the agebytes map was incorrectly
calculated: it assumed the transactions in the mempool all have unique
timestamps at second-granularity. This commit fixes this by correctly
finding the right cumulative number of transactions in the map suffix.

This bug could lead to an out-of-bounds write in the rare case that
all transactions in the mempool were received (and added to the mempool)
at a rate of at least 50 transactions per second. (More specifically,
the number of *unique* receive_time values, which have second-
granularity, must be at most 2% of the number of transactions in the
mempool for this crash to trigger.) If this condition is satisfied, 'it'
points to *before* the agebytes map, 'delta' gets a nonsense value, and
the value of 'i' in the first stats.histo-filling loop will be out of
bounds of stats.histo.
This commit is contained in:
Tom Smeding 2019-08-28 16:46:31 +02:00
parent 85014813cf
commit 6bbc646e6f

View file

@ -746,8 +746,15 @@ namespace cryptonote
/* If enough txs, spread the first 98% of results across
* the first 9 bins, drop final 2% in last bin.
*/
it=agebytes.end();
for (size_t n=0; n <= end; n++, it--);
it = agebytes.end();
size_t cumulative_num = 0;
/* Since agebytes is not empty and end is nonzero, the
* below loop can always run at least once.
*/
do {
--it;
cumulative_num += it->second.txs;
} while (it != agebytes.begin() && cumulative_num < end);
stats.histo_98pc = it->first;
factor = 9;
delta = it->first;