2020-01-17 11:28:23 +00:00
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Operators shown here are purely for design experimentation and may not reflect the final system of operators:
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2019-12-26 05:23:33 +00:00
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2019-12-26 05:19:18 +00:00
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## Make me a square!
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Keg got 11 bytes on this challenge.
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2019-12-26 05:23:33 +00:00
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P[DD+s}S3
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2019-12-26 05:19:18 +00:00
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2019-12-26 05:20:25 +00:00
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Expands to:
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2019-12-26 05:19:18 +00:00
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2019-12-26 05:23:33 +00:00
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Shape(Palindromise(Add(Double(Double(input)), Space)), 3)
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2019-12-26 05:20:25 +00:00
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2019-12-26 05:23:33 +00:00
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9 bytes (Ket) vs 11 bytes (Keg) .
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2019-12-26 05:27:40 +00:00
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## Output Distinct Factor Cubiods
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2020-01-17 11:28:23 +00:00
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Keg didn't participate in this challenge.
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2019-12-26 05:27:40 +00:00
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*R=
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F?f^
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Psuedo:
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function f
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reduce the input via multiplication
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return that result equal to the input
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function main
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generate factors of input
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filter list by above flow (f)
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2019-12-26 05:36:02 +00:00
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## Swap good and bad
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2020-01-17 11:28:23 +00:00
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Keg got 7 bytes on this challenge (first place incidentally).
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2019-12-26 05:36:02 +00:00
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-"....
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Note that this uses a reverse token flag. But that's what the keg answer does.
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6 bytes (Ket) vs 7 bytes (Keg).
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2019-12-26 08:32:19 +00:00
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## N(e(s(t))) a string
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2020-01-17 11:28:23 +00:00
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Keg got 12 bytes.
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2019-12-26 08:32:19 +00:00
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M\(+\)*!
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ININIM
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Add(Map(input, "("), Times(")", length(input)))
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`--mapoffbyone`
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8 bytes (Ket) vs 12 bytes (Keg)
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2019-12-26 08:35:26 +00:00
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## DDoouubbllee SSppeeaakk
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2020-01-17 11:28:23 +00:00
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Keg got 3 bytes.
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2019-12-26 08:35:26 +00:00
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i
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interleave(input, input)
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1 byte (Ket) vs 3 bytes (Keg)
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